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Darlington Pair Calculator

Estimate the combined current gain of two cascaded BJTs, or calculate the base current or collector current available from a Darlington pair.

The calculator also reports the combined base-emitter voltage and a VCE(sat)-based conduction-power reference for transistor drivers and switching circuits.

Engineering tool

Darlington Pair Calculator

Calculate combined transistor gain, base or collector current, equivalent VBE, and saturation power reference.

Calculation mode

DC current gain of the input transistor.

DC current gain of the output transistor.

Base-emitter drop of Q1.

Base-emitter drop of Q2.

Combined gain

10,000 βtotal

Result console

Combined current gain
10,000βtotal
Equivalent VBE
1.4V

The product-gain model is an engineering estimate. Verify device gain, current sharing, VBE, VCE(sat), temperature, and safe operating area from the datasheet.

Two-stage NPN Darlington pairInput base current drives transistor Q1. The emitter of Q1 drives Q2, whose collector supplies output current to the load.Input IbQ1 / β1Q2 / β2LoadOutput IcVBE1 + VBE2VCE(sat)GND
Cascaded NPN transistors provide high current gain with two base-emitter drops.

Formula reference

Darlington Pair Formulas

The gain-product model is a first-order estimate; use datasheet curves and limits for production design.

Combined gain: βtotal ≈ β1 × β2Base current: Ib = Ic / βtotalCollector current: Ic = Ib × βtotalEquivalent VBE: VBE(total) ≈ VBE1 + VBE2Power reference: P ≈ VCE(sat) × Ic

Variable definitions

β1
input transistor DC current gain
β2
output transistor DC current gain
Ib
Darlington input base current
Ic
estimated output collector current
VCE(sat)
saturated pair voltage drop

Worked Example

1 A Darlington Driver

β1 = 100, β2 = 100, Ic = 1 A

βtotal ≈ 100 × 100 = 10,000

Ib = 1 A / 10,000 = 100 µA

VBE(total) ≈ 0.7 V + 0.7 V = 1.4 V

At VCE(sat) = 1 V, the conduction-power reference is approximately 1 W.

Engineering Notes

Very high current gain

Darlington pairs provide very high current gain from a small input base current.

Two junction drops

Total VBE is roughly two base-emitter drops and raises the required input voltage.

Higher saturation loss

Saturation voltage is higher than a single BJT and can create substantial heat at high current.

Slower switching

Switching speed is slower due to stored charge in the cascaded transistor structure.

Compare with MOSFETs

Logic-level MOSFETs are often better for high-efficiency switching and low drive power.

Support reference

FAQ

What is a Darlington pair?

A Darlington pair connects the emitter of one BJT to the base of a second BJT so their current gains multiply approximately. It provides high current gain from a small input current.

How do you calculate Darlington gain?

For a quick engineering estimate, multiply the two transistor gains: βtotal ≈ β1 × β2. Real gain depends on device current, temperature, loading, and topology.

Why is Darlington VBE higher?

The input signal must forward-bias two base-emitter junctions in series, so the total input threshold is approximately VBE1 + VBE2, often around 1.2 to 1.4 V for silicon devices.

Why is Darlington saturation voltage higher?

The cascaded junction arrangement prevents the output transistor from saturating like an isolated BJT. Darlington VCE(sat) is commonly much higher, increasing conduction loss.

When should I use a MOSFET instead?

A logic-level MOSFET is often preferable for efficient switching, low drive current, lower conduction loss, or faster switching. Verify gate threshold, RDS(on), voltage rating, and switching conditions.

Documentation

Design notes, guides, and engineering articles linked to this tool.