Motor Gear Ratio & Output Calculator
Calculate gearbox output RPM, output torque, required motor RPM, required motor torque, gear tooth ratio, multi-stage ratio, total gearbox efficiency, mechanical power balance, and gearbox loss for motor-drive sizing references.
MOT-009 uses one fixed convention: gear ratio G equals input or motor shaft speed divided by output shaft speed. A 10:1 reduction is therefore G = 10. Gearbox efficiency is mechanical gearbox efficiency, not motor electrical efficiency.
Engineering tool
Motor Gear Ratio & Output Calculator
Calculate motor gearbox output RPM, output torque, required input speed, required motor torque, gear tooth ratio, multi-stage ratio, efficiency, power balance and gearbox losses.
Calculation mode
Parameter panel
Result console
- Output RPM
- 300RPM
- Output Torque
- 9N·m
- Output Power
- 282.743W
- Gearbox Loss
- 31.4159W
Motor speed and motor torque must describe the same operating point. Do not combine no-load RPM with stall torque as if they occur simultaneously.
Reference table
| Input Mechanical Power | 314.159 | W |
|---|---|---|
| Expected Pout = Pin × ηg | 282.743 | W |
| Power Balance Error | 0 | W |
| Torque Multiplication Factor | 9 | × |
Motor Gear Ratio & Output Formula Audit
| Gear Ratio Definition | ECParts defines G = input/motor shaft speed divided by output shaft speed. |
|---|---|
| Reduction Convention | A 10:1 reduction uses G = 10, so nout = nin / G. |
| Overdrive Convention | Ratios below 1 are allowed and represent output speed greater than input speed. |
| Output Speed Formula | nout = nin / G. |
| Required Input Speed | nin = nout × G. |
| Ideal Output Torque | τout,ideal = τin × G. |
| Efficiency-Adjusted Torque | τout = τin × G × ηg. |
| Required Input Torque | τin = τout / (G × ηg). |
| Gearbox Efficiency | ηg is gearbox mechanical efficiency, not motor electrical efficiency. |
| Power Balance | Pout = τout × ωout and should equal Pin × ηg under the adopted model. |
| Double-Counting Protection | Efficiency is applied once through output torque; output power is then computed from τout × ωout. |
| Ratio from Speed | Gspeed = nin / nout. |
| Ratio from Torque | Gtorque = τout / (τin × ηg). |
| Gear Tooth Ratio | For a simple external pair, G = Zdriven / Zdriver. |
| Multi-Stage Ratio | Gtotal = G1 × G2 × ... × Gn. |
| Multi-Stage Efficiency | ηtotal = η1 × η2 × ... × ηn. |
| Motor Operating Point | Motor torque and motor speed must belong to the same operating point. |
| Stall / No-Load Boundary | Do not combine stall torque with no-load RPM as a real output point. |
| Backlash Boundary | Backlash, compliance and lost motion are not represented by ideal ratio equations. |
| Dynamic Torque Boundary | Acceleration torque and reflected inertia are outside V1. |
| MOT-001 Boundary | MOT-001 owns generic shaft torque, speed and power relationships. |
| MOT-005 Boundary | MOT-005 owns motor efficiency; this page only models gearbox mechanical efficiency. |
| MOT-008 Boundary | MOT-008 owns encoder RPM and encoder placement references. |
Formula
Formula reference
Motor gear ratio and gearbox output formulas
Efficiency is applied once to output torque. Output mechanical power is then calculated from adjusted output torque and output speed.
G = nin / noutnout = nin / Gnin = nout × Gτout,ideal = τin × Gτout = τin × G × ηgτin = τout / (G × ηg)Pin = τin × ωinPout = τout × ωoutPout ≈ Pin × ηgPloss = Pin - PoutGteeth = Zdriven / ZdriverGtotal = G1 × G2 × ... × Gnηtotal = η1 × η2 × ... × ηnVariable definitions
- G
- gear ratio using input speed divided by output speed
- nin
- motor or gearbox input speed
- nout
- gearbox output speed
- τin
- motor/input shaft torque
- τout
- gearbox output shaft torque
- ηg
- gearbox mechanical efficiency
- Zdriver
- driver gear teeth
- Zdriven
- driven gear teeth
Motor Gear Ratio & Output Formula Audit
| Gear Ratio Definition | G = input/motor shaft speed divided by output shaft speed. |
|---|---|
| Reduction Convention | 10:1 reduction uses G = 10. |
| Overdrive Convention | G < 1 is allowed and represents output speed greater than input speed. |
| Output Speed Formula | nout = nin / G. |
| Required Input Speed Formula | nin = nout × G. |
| Ideal Output Torque Formula | τout,ideal = τin × G. |
| Efficiency-Adjusted Torque Formula | τout = τin × G × ηg. |
| Required Input Torque Formula | τin = τout / (G × ηg). |
| Gearbox Efficiency Definition | ηg is gearbox mechanical efficiency from 0 to 1, not motor electrical efficiency. |
| Power Balance | Pout = τout × ωout ≈ Pin × ηg. |
| Efficiency Double-Counting Protection | Efficiency is applied once in torque; output power is computed from adjusted torque and output speed. |
| Ratio from Speed | Gspeed = nin / nout. |
| Ratio from Torque | Gtorque = τout / (τin × ηg). |
| Gear Tooth Ratio | Simple external pair: G = Zdriven / Zdriver. |
| Multi-Stage Ratio | Gtotal = G1 × G2 × ... × Gn. |
| Multi-Stage Efficiency | ηtotal = η1 × η2 × ... × ηn. |
| Motor Operating-Point Boundary | Motor RPM and torque must be from the same operating point. |
| Stall Torque / No-Load Boundary | Stall torque and no-load RPM cannot be combined as a real gearmotor output point. |
| Backlash Boundary | Backlash, compliance and lost motion are outside the ideal ratio equations. |
| Dynamic Torque Boundary | Acceleration torque, inertia reflection and duty-cycle sizing are outside V1. |
| MOT-001 Scope Boundary | MOT-001 owns generic shaft power from torque and speed. |
| MOT-005 Scope Boundary | MOT-005 owns motor efficiency; MOT-009 owns gearbox mechanical efficiency. |
| MOT-008 Scope Boundary | MOT-008 owns encoder pulse/count RPM and encoder placement references. |
Worked Examples
| Example | Calculation | Result |
|---|---|---|
| Output RPM | Motor = 3000 RPM, G = 10 | Output = 300 RPM |
| Required Motor RPM | Output = 300 RPM, G = 10 | Motor = 3000 RPM |
| Ideal Output Torque | τin = 1 N·m, G = 10, η = 100% | τout = 10 N·m |
| Efficiency Torque | τin = 1 N·m, G = 10, η = 90% | τout = 9 N·m |
| Required Input Torque | τout = 9 N·m, G = 10, η = 90% | τin = 1 N·m |
| Ratio from Speed | Motor = 3000 RPM, target = 300 RPM | G = 10 |
| Ratio from Torque | τin = 1 N·m, target = 9 N·m, η = 0.9 | G = 10 |
| Gear Teeth Ratio | Driver = 20, driven = 100 | G = 5 |
| Gear Teeth Output | Input = 1000 RPM, 20 → 100 gear | Output = 200 RPM |
| Two Stages | G1 = 3, G2 = 4 | Gtotal = 12 |
| Two Efficiencies | η1 = 0.9, η2 = 0.8 | ηtotal = 0.72 |
| Multi-Stage Speed | Gtotal = 12, input = 1200 RPM | Output = 100 RPM |
| Multi-Stage Torque | τin = 1 N·m, Gtotal = 12, ηtotal = 0.72 | τout = 8.64 N·m |
| Input Power | τ = 1 N·m, RPM = 3000 | Pin ≈ 314.159 W |
| Output Power | G = 10, η = 0.9, output = 300 RPM and 9 N·m | Pout ≈ 282.743 W |
| Power Balance | Same example | Pout = 0.9 × Pin |
| Gearbox Loss | Same example | Loss ≈ 31.416 W |
| 1:1 Ideal | G = 1, η = 1 | Speed and torque unchanged |
| 1:1 Lossy | G = 1, η = 0.8 | Speed unchanged, torque = 0.8 × input |
| Overdrive Speed | G = 0.5, input = 1000 RPM | Output = 2000 RPM |
| Overdrive Torque | G = 0.5, η = 1, input = 10 N·m | Output = 5 N·m |
| Zero Efficiency | η = 0 | Rejected |
| Over-Unity Efficiency | η = 120% | Rejected |
| Constraint Mismatch | Gspeed = 10, Gtorque = 12 | Flag mismatch |
| Speed Round Trip | RPM → output → input | Original RPM recovered |
| Torque Round Trip | Torque → output → required input | Original torque recovered |
Engineering Notes
| Motor Gear Ratio | ECParts uses input speed divided by output speed for every MOT-009 mode. |
|---|---|
| Gear Reduction | A reduction lowers speed and raises torque under the adopted convention. |
| Gearbox | The model is an idealized mechanical transfer with a single efficiency term. |
| Output RPM | Output speed equals input speed divided by G. |
| Output Torque | Efficiency-adjusted output torque equals input torque times G times ηg. |
| Torque Multiplication | The effective torque multiplication factor is Gηg. |
| Gearbox Efficiency | Efficiency may vary with load, speed, lubrication, temperature and direction. |
| Mechanical Power | A gearbox does not create mechanical power; real output power is lower than input power. |
| Gear Teeth | A simple external driver/driven pair uses driven teeth divided by driver teeth. |
| Multi-Stage Gearbox | Stage ratios and stage efficiencies multiply. |
| Overdrive | G below 1 increases speed and reduces torque. |
| Backlash | Backlash and compliance affect motion but are not included in the ideal equations. |
| Motor Operating Point | Input torque and input speed must come from the same motor operating point. |
| Torque-Speed Curve | Changing the ratio changes the load line and can move the motor operating point. |
| Static Torque | V1 assumes steady shaft torque and does not include acceleration torque. |
| Non-Backdrivable Gearbox | Some worm or self-locking mechanisms cannot use one efficiency value for reverse drive. |
Common Mistakes
- Writing a 10:1 reduction as G = 0.1.
- Multiplying output RPM by G instead of dividing input RPM by G.
- Dividing output torque by G instead of multiplying input torque by G.
- Applying gearbox efficiency twice.
- Adding multi-stage efficiencies instead of multiplying them.
- Adding multi-stage ratios instead of multiplying them.
- Accepting efficiency above 100%.
- Rejecting G < 1 instead of treating it as overdrive.
- Swapping driver and driven gear teeth.
- Combining stall torque with no-load RPM.
- Confusing gearbox efficiency with motor electrical efficiency.
- Treating remaining mechanical power as motor efficiency.
- Ignoring that a new gear ratio can change the real motor operating point.
- Assuming backlash-free positioning from ideal gear ratio alone.
Support reference
FAQ
How do I calculate motor gear ratio?
ECParts defines gear ratio as G = input or motor shaft speed divided by output shaft speed. A 10:1 reduction therefore uses G = 10.
How do I calculate output RPM from motor RPM?
Use nout = nin / G, where nin is motor or input RPM and G is the gear ratio under the ECParts input/output convention.
How do I calculate required motor RPM from output RPM?
Use nin = nout × G. For a 300 RPM output and a 10:1 reduction, the motor must run at 3000 RPM.
How do I calculate output torque after a gearbox?
Ideal output torque is τin × G. With gearbox efficiency, use τout = τin × G × ηg.
How does gearbox efficiency affect output torque?
Efficiency reduces the ideal torque multiplication. A 10:1 gearbox with 90% efficiency has an effective torque multiplication of 9×.
How do I calculate required motor torque?
Use τin = τout / (G × ηg). Efficiency must be greater than zero for a finite input torque result.
How do I calculate the required gear ratio for a target speed?
Use Gspeed = motor RPM / target output RPM. This only satisfies the speed constraint.
How do I calculate the required gear ratio for a target torque?
Use Gtorque = required output torque / (motor torque × gearbox efficiency).
What does a 10:1 gear ratio mean?
With the adopted convention, 10:1 means the motor or input shaft turns about 10 revolutions for 1 output revolution.
Does a gearbox increase motor power?
No. A gearbox trades speed for torque. Ideal mechanical power is conserved, and real output power is lower because of gearbox loss.
Why does torque increase when speed decreases?
For an ideal reduction gearbox, speed decreases by G while torque increases by G, keeping mechanical power approximately constant before losses.
How do I calculate gear ratio from gear teeth?
For a simple external gear pair, G = driven teeth / driver teeth. A 20-tooth driver and 100-tooth driven gear gives G = 5.
How do I calculate a multi-stage gear ratio?
Multiply the stage ratios: Gtotal = G1 × G2 × ... × Gn. Do not add the ratios.
How do I combine gearbox efficiencies?
Multiply the stage efficiencies as fractions. For 90% and 80%, ηtotal = 0.9 × 0.8 = 0.72.
What does a gear ratio below 1 mean?
Under the ECParts convention, G below 1 means overdrive or speed increase: output speed is greater than input speed and torque is reduced.
Does a gearbox change motor operating point?
Yes. Changing gear ratio can change motor load torque, speed, current and efficiency. This page is a kinematic and mechanical power reference, not a full motor selection model.
Can I combine motor stall torque with no-load RPM?
No. Stall torque and no-load speed occur at different operating points and must not be combined as one real output condition.
How does gearbox backlash affect output?
Backlash, compliance and lost motion are not included in the ideal ratio equations, but they can affect positioning and small-motion behavior.
What is the difference between motor efficiency and gearbox efficiency?
Motor efficiency converts electrical input to motor shaft output. Gearbox efficiency converts input mechanical shaft power to gearbox output mechanical power.
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